56x^2+18x-8=0

Solution for 56x^2+18x-8=0 equation:

56x^2+18x-8=0

a = 56; b = 18; c = -8;
Δ = b2-4ac
Δ = 182-4·56·(-8)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-46}{2*56}=\frac{-64}{112}
=-4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+46}{2*56}=\frac{28}{112}
=1/4
$